what is power of torch bulb rated at 2.5v and 500mA?
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Answered by
10
we have,P=VI
=2.5* 500/1000 (as 1 mA= 1/1000 A)
=25/10 * 1/2
=5/4 Watt = 1.25 W
hope,this helps!
Answered by
1
It measures the work done n
per unit charger.
It is defined as the difference in
electric potential between two points in an electric field,equal to the work
done per unit quantity of charge in moving it from one point to another
in an electrostatic field
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