Question

What is pressure acting at the bottom of a beaker if the weight pf the water is 6N and 0.002 m square is area. Give me the full process.
​

Answer 1

Answer:

The force exerted by the water at the bottom of the beaker is 6Newton

(wieght is the force with which the earth attract that object)

acting on an area 0.002m^2

The pressure is

$p = \frac{f}{a} \\ p = \frac{6n}{0.002m {}^{2} } \\ pressure = 3000pascal$