Question

What is principal when simple interest is 82 rate is 5%time is2 year

Answer 1

Answer:

THE PRINCIPAL IS ₹820

Step-by-step explanation:

PARAMETERS GIVEN,

SI = ₹82

RATE% = 5%

TIME = 2 YEAR

SO,

LET THE PRINCIPAL BE x

SO,

WE KNOW,

SI = PRT/100

₹82 = (x*5*2)/100

x = (₹82*100)/5*2

x = ₹820

SO,

THE PRINCIPAL IS ₹820

I HOPE YOU UNDERSTOOD THE QUESTION!!!

                           !!!JAI SHREE KRISHNA!!!

Answer 2

Required Solution:

Given:

• Simple Interest ( S.I ) = Rs 82

• Rate of interest ( R ) = 5%

• Time ( T ) = 2 years

To find:

• Principal ( P )

Solution:

By using the formula of Simple interest:

• ${\underline {\boxed {\Large {\bf \gray { S.I = \dfrac{P \times R \times T}{100} } }}}}$

                       

$\sf { \longmapsto 82 = \dfrac{ P \times 5 \times 2}{100} }$

                       

$\sf { \longmapsto 82 \times 100 = P \times 10 }$

                       

$\sf { \longmapsto 8200 = P \times 10 }$

                       

$\sf { \longmapsto \cancel{\dfrac{8200}{10} }= P }$

                       

$\longmapsto$ ${\underline {\boxed {\large {\mathfrak \purple { Principal = 820 } }}}}$

                       

$\underline { \sf { \therefore Principal \: amount \: is \: \textsf{\textbf { Rs \: 820 }} }}$

                       

Let us verify it!

                       

• ${\underline {\boxed {\Large {\bf \gray { S.I = \dfrac{P \times R \times T}{100} } }}}}$

                       

$\sf { \longmapsto 82 = \dfrac{ 82\cancel{0} \times 5 \times 2}{10\cancel{0}} }$

                       

$\sf { \longmapsto 82 = \dfrac{ 82 \times \cancel{10}}{\cancel{10}} }$

                       

$\longmapsto$ ${\underline {\boxed {\large {\mathfrak \purple { 82 = 82 } }}}}$

                       

$\underline { \sf { \therefore Principal \: amount \: is \: \textsf{\textbf { Hence, L.H.S \: is \: equal \: to \: R.H.S }} }}$

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