Question

What is probability of two friends having same birthday if leap year ingnored.

Answer 1

Answer:

Step-by-step explanation:

1 year = 365 days and the birthday should be in the same day therefore P(E) = Number of favourable outcome/Total number of outcomes.

That is, 1/365.

Answer 2

$\rightarrow\huge\text{Answer}$

☛ total number of days n(s)= 365

we know that two different friend birthday was same on 1 day in a year

so ,

365-1= 364 days are different for each friend

so, n(E)=364

therefore ,

p(E)= n(E)/n(S)

= 364/365