what is probability that a non-leap year selected at random will contain 53 sundays
DonDj:
1/7 is correct answer
Answers
Answered by
7
HEYA.!!!
The probability of getting is 53/365
P(E)= no .of favorable outcomes.
_____________________
total no.of outcomes
=53/365
(total Sundays =53 and total days in year =365)
Hope it helps u.. :)
The probability of getting is 53/365
P(E)= no .of favorable outcomes.
_____________________
total no.of outcomes
=53/365
(total Sundays =53 and total days in year =365)
Hope it helps u.. :)
hi... thnks but can u send me how u did it
its *wrong*
then pls send me the correct answer
1/7
ooooooo....thnks
wc
Answered by
5
1/7 is correct answer as One day selected as sunday-monday-tuesday.....................
thnk u
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