Question

What is probable value of mean deviation when Q3 =40 and Q1 = 15

Answer 1

Answer:

MD = 15

Step-by-step explanation:

Q3=40 Q1=15

THEREFORE QD= Q3-Q1 / 2

QD= 40-15 / 2

=25 / 2

=12.5

WKT, 6QD=5MD=4SD

MD= 6 * 12.5 /5

MD=15

Answer 2

The probable value of mean deviation is 15

Given :

Q₃ = 40 , Q₁ = 15

To find :

The probable value of mean deviation

Solution :

Step 1 of 2 :

Find quartile deviation

Here it is given that Q₃ = 40 , Q₁ = 15

So Quartile deviation

= QD

$\displaystyle \sf{ = \frac{Q_3 -Q_1 }{2} }$

$\displaystyle \sf{ = \frac{40 - 15 }{2} }$

$\displaystyle \sf{ = \frac{25 }{2} }$

$\displaystyle \sf{ = 12.5 }$

Step 2 of 2 :

Find mean deviation

Thus mean deviation

= MD

$\displaystyle \sf{ = \frac{6}{5} \times Q.D}$

$\displaystyle \sf{ = \frac{6}{5} \times 12.5}$

$\displaystyle \sf{ = 15}$

Hence the required probable value of mean deviation = 15

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