What is probablilty that two heads do not occur consecutively when a fair coin is tossed 10 times ?
Answers
Answered by
1
hii dear here is your answer
let us take in the first attempt we got head (prob =1/2) next we should get in 3 rd time next 5th time ,7 th time ,9 th time total 5 times so total prob is 1/2^5
and if we got head in second time -> 2nd ,4 th, 6th,8 th 10 th total 5 times
sum the both === 1/2^5 +1 /2^5 = 2(1/2^5)= 1/2^4
hope it helps you.....
let us take in the first attempt we got head (prob =1/2) next we should get in 3 rd time next 5th time ,7 th time ,9 th time total 5 times so total prob is 1/2^5
and if we got head in second time -> 2nd ,4 th, 6th,8 th 10 th total 5 times
sum the both === 1/2^5 +1 /2^5 = 2(1/2^5)= 1/2^4
hope it helps you.....
Similar questions