Question

What is projectile? Show that the path of aprojectie is a parabola

Answer 1

Explanation:

A body or object upwards at an angle theta other than 90° with horizontal is called projectile. ♤Let projectile is thrown with a initial velocity u at an angle theta there with horizontal. This equation represents equation of parabola. Hence path of projectileq

Answer 2

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Let a body is projected with speed um/sinclined θ with horizontal line.

Then, vertical component of u, uy=ucosθ

Horizontal component of ux=usinθ

acceleration on horizontal, ax=0

acceleration on vertical, ay=−g

Now, use formula 

X=uxt

X=ucosθ.t

t=X/ucosθ--------------------------(1)

Again, y=uyt+1/2ayt2

y=usinθt−1/2gt2

put equation  (1) here,

y=usinθ×x/ucosθ−1/2gt2×x2/u2cos2θ

=tanθx−1/2gx2/u2cos2

y=tanθ.x−1/2gx2/u2cos2θ

this equation is similar to standard equation of parabola y=ax2+bx+c her, a,band c are constant

So, A projectile motion is parabolic motion.

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