Question

what is pure form result when sodium hydroxide is mixed with iodine??...​

Answer 1

Step-by-step explanation:

Sodium iodide forms adducts with sodium hydroxide of the NaI·2NaOH (mp 225-230°C) and NaI·3NaOH (mp 215-220°C) compositions. Sodium iodate in the presence of NaOH disproportionates to iodide and orthoperiodate according to the reaction NaIO3 + 3NaOH → 1/4NaI + 3/4Na5IO 6 + 3/2H2O. The process begins at ∼270°C and ends at ∼420°C (melting of NaIO3). In the presence of NaOH, sodium meta-periodate NaIO4 decomposes (as in the pure state) at 290°C to NaIO3 and O2, but with the formation of ∼5% Na 5IO6

Answer 2

Answer:

It is produced industrially as a salt formed when acidic iodides react with sodium hydroxide. It is a chaotropic salt..