Question

what is rate of disappearance of H2 in mol/l/hour if the experimental rate of appearance HI by the reaction H2 + I2→ 2 HI is 8.4 x 10^-6 mol/l/s?​

Answer 1

Answer:

2.0×10−4mol L−1s−1

H2(g)+I2(g)→2HI(g)

dt−d[H2]=+dtd[HI]

∴dtd[HI]=2×dtdH2=2×1×10−4=2×10−4moll−1s−1

Explanation:

hope it helps you..please mark me as brainlist