Question

what is rectangle find the perimeter if area is 200cm^2 and breadth =l\4 .

Answer 1

$\mathfrak{dear\:user}$

$\mathfrak{question-what \:is \:rectangle \:and \:do \:the \:sum}$

$\mathfrak{here\:is\:the\:solution}$

$\mathbb{ANSWER}$

$\textsc{ a rectangle is a quadrilateral with four right angles. }$

$\textsc{Number of vertices: 4}$

$\textsc{Number of edges: 4}$

$\textsc{Internal angle: 90}$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large B or A/4 }\multiput(-1.4,1.4)(6.8,0){2}{\sf\large l }\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

$\textsf{Area=length x breadth }$

$\textsf{A=area,L=Length,B=breadth}$

$\textsf{A=L x B }$

$\boxed{\textsf{A=l x b}}\to 1$

$\textsf{Perimter=Sum of all sides }$

$\textsf{P=Perimeter,L=Length,B=Breadth}$

$\textsf{P=L+B+L+B}$

$\textsf{P=L+L+B+B}$

$\textsf{P=2L+2B}$

$\textsf{P=2(L+B)}$

$\boxed {\textsf P=2(L+B)}}\to 2$

$\text{A=B x L ,when L is not given and Area ,Breath are given }$

$\text{A=L x B}\\\text{A/B=L}\\\\text{L=A/B }\\\\\\boxed{L=A/B}\to3$

$\text{Given -area=200cm}$

$\text{from 1 }\boxed{\textsf {A=L x B }}$

$\to \textsf{the question is wrong so B=A/4 }$

$\text{B=A/4\:\:where A(area)=200,so 200/4=50}$

${\text{from 3\:\boxed{L=A/B}}$

$\text{L=200/50 }$

$\text{L=4cm\\}$

$\boxed{\textsf{L=4}}$

$\texttt{from 2 \boxed {P=2(L+B)}}$

$\text{P=2(4+50)}\\\text{P=2(54)}\\\text{P=108}$

$\boxed{\textsf{P=108 cm}}$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 50cm(B) }\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 4cm(L) }\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

$\mathbb{EXTRA \:INFORMATION}$

$\textbf{How to draw a rectangle?}$

$\textsf{For example take the values of B=9cm , L=10cm}$

$\bullet \textsf{draw a horizonal line AB of 10cm(length)}$

$\bullet\textsf{draw a right angle from the point A and draw a line AD of 9cm (breadth)}$

$\bullet\textsf{From D draw a right angle and draw a line DC of 10cm(length)}$

$\bullet\textsf{From C draw a right angle and draw a line CB of 9cm(breadth)}$

$\bullet \textsf{refer to images for understanding more}$

$\textbf{Properties of rectangle}$

$\textsf{The opposite sides are parallel and equal to each other}$

$\textsf{Each interior angle is equal to 90 degrees}$

$\textsf{The sum of all the interior angles is equal to 360 degrees}$

$\textsf{The diagonals bisect each other}$

$\textsf{Both the diagonals have the same length}$

$\textsf{A diagonal of a rectangle is a diameter of its circumcircle}$

$\to PLESE \:DON'T\:COPY$

$\to CODES\:USED$

$\bigstar \:mathfrak\\\bigstar \:mathcal\\\bigstar \:mathbb\\\bigstar \:mathbf\\\bigstar \:textit\\\bigstar \:textsf\\\bigstar \:textsc$

$\mathcal{HOPE \:IT \:HELPS}$

$\mathcal{BY\;BRAINLY\:ROSHAN}$

Answer 2

A=B x L ,when L is not given and Area ,Breath are given

\begin{gathered}\text{A=L x B}\\\text{A/B=L}\\\\text{L=A/B }\\\\\\boxed{L=A/B}\to3\end{gathered}

A=L x B

A/B=L

textL=A/B

boxedL=A/B→3

\text{Given -area=200cm}Given -area=200cm

\text{from 1 }\boxed{\textsf {A=L x B }}from 1

A=L x B

$</p><p>\begin{gathered}\text{A=L x B}\\\text{A/B=L}\\\\text{L=A/B }\\\\\\boxed{L=A/B}\to3\end{gathered} </p><p>A=L x B</p><p>A/B= \\ L</p><p>textL= \\ A/B</p><p>boxedL=A/B \\ →3</p><p> </p><p> </p><p></p><p>\text{Given -area=200cm} \\ Given -area=200cm</p><p></p><p>\text{from 1 }\boxed{\textsf {A=L x B }} \\ from 1 </p><p>A=L x B$

\to \textsf{the question is wrong so B=A/4 }→the question is wrong so B=A/4

\text{B=A/4\:\:where A(area)=200,so 200/4=50}B=A/4where A(area)=200,so 200/4=50

{\text{from 3\:\boxed{L=A/B}}

\text{L=200/50 }L=200/50