Question

What is relation between current and drift velocity?

.
.
Draw the grap.
​

Answer 1

$\huge \mathfrak \pink {Hey \: Jaanu!}$

$\huge</strong><strong>\</strong><strong>y</strong><strong>e</strong><strong>l</strong><strong>l</strong><strong>o</strong><strong>w</strong><strong>{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{</strong><strong>R</strong><strong>e</strong><strong>l</strong><strong>a</strong><strong>t</strong><strong>i</strong><strong>o</strong><strong>n</strong><strong>\:</strong><strong> </strong><strong>b</strong><strong>e</strong><strong>t</strong><strong>w</strong><strong>e</strong><strong>e</strong><strong>n</strong><strong>\:</strong><strong> </strong><strong>c</strong><strong>u</strong><strong>r</strong><strong>r</strong><strong>e</strong><strong>n</strong><strong>t</strong><strong>\:</strong><strong> </strong><strong>a</strong><strong>n</strong><strong>d</strong><strong>\:</strong><strong> </strong><strong>d</strong><strong>r</strong><strong>i</strong><strong>f</strong><strong>t</strong><strong> </strong><strong>\:</strong><strong>v</strong><strong>e</strong><strong>l</strong><strong>o</strong><strong>c</strong><strong>i</strong><strong>t</strong><strong>y</strong><strong>.</strong><strong>}}}}}}}$

♦I = nAevd

1. Where n is the electron density or no. of electrons per unit volume of the conductor and A is the area of cross section of the conductor.
2. The small value of the drif velocity produces a large amount of current due to presence of large number of free electrons in a conductor.
3. The propagation of current is at the speed of light.

♦And your graph for Ohm's law is provided above.

Hope it helps you! ❤

Answer 2

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{Answer}}}}}}$

Relation Between Current and Drift Velocity

consider a conductor of length l and uniform age of cross section A

Let n new the number of free electrons per unit volume in metal

when a potential difference V is applied across the conductor the electric field E=v/l

because of the electric field the free electrons drift opposite to the electric field with drift velocity vd

let the distance moved by free electrons equal to vd ∆t[short interval of time

volume of conductor=Avd∆t

the number of electrons drifting in this volume is nAvd∆t

charge of electron=negative

so the total charge transportated accross area A is -enAvd∆t

thus,the amount of charge transported in a time ∆t across the area of cross section A in direction opposite to electric field is ∆Q=enAvd∆t

if l is the magnitude of the current in the conductor ∆Q=l∆t

thus l∆t= ne A vd∆t --------1

l=n e A vd

gives the relationship between current and drift velocity

$<marquee direction="left">$Hoקe Ꭵt ђelקs