Question

what is result of d/dx(cot inverse x)

Answer 1

Answer:

let cot^-x=y

=>x=coty

now d/dx(x)=d/dx(coty)

=>1=-cosec^2y dy/dx

=>dy/dx=1/-cosec^2y

=1/1+cot^2y

now putting x=coty

=>d/dx(cot^-1)=1/1+x^2

I hope it will help u ❤️plz give me brilliant..