Question

what is rise in temperature of a collective drop when initially 1gm and 2gm travel with velocities 10cm/sec and 15cm/sec ?​

Answer 1

Answer:

I think kinetic energy of both drops will change into heat energy like ………..

1/2[(m1×v1^2)+( m2×v2^2)]= m(total)× specific heat of water × change in tempreture….(1)

Specific heat of water is 4.18 joule per gram per °c and m (total) is 3 gram which is equal to…. m1+m2.

After solving equation (1) we get rise in tempreture = 21.56°c

Explanation:

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Answer 2

Answer:

kinetic energy of both drops will change into heat energy like :

1/2[(m1×v1^2)+( m2×v2^2)]= m(total)× specific heat of water × change in tempreture….(1)

Specific heat of water is 4.18 joule per gram per °c and m (total) is 3 gram which is equal to…. m1+m2.

After solving equation (1) we get rise in tempreture = 21.56°c

Explanation:

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