Question

What is role of moment of inertia, theta, phi to develop polymer crystalline/amorphous dimension?​

Answer 1

Crystalline and polymer dimensions are plastic materials that are used in daily life. The moment of inertia helps to the dimensions.

Explanation:

• The moment of inertia is  
• L = I x ω
• Now L = r x p
• Put the value of L
• r x p = I x ω
• [L] [MLT^2] = I T^-1
• As we know that T = 2π / ω
• I = [ML^2]
• h / I = ML^2T^-1 / ML^2 = T^-1

Answer 2

Answer :-

Crystalline and polymer dimensions are plastic materials that are used in daily life. The moment of inertia helps to the dimensions.

Explanation:

The moment of inertia is  

• L = I x ω

• Now L = r x p

• Put the value of L

• r x p = I x ω

• [L] [MLT^2] = I T^-1

• As we know that T = 2π / ω

• I = [ML^2]

• h / I = ML^2T^-1 / ML^2 = T^-1