Question

What is S-2 in a 0.050M solution of H2S ?Ka1=1.1×10^-7 and Ka2=1.0×10^-14

Answer 1

Answer:

Ka1 = 1.1 × 10^(-7) = [H⁺][HS⁻]/[H₂S] and Ka2 = 1.0 × 10^(-14) = [H⁺][S²⁻]/[HS⁻]

The two quantities [H⁺] and [HS⁻] are virtually equal, as a negligible number of H⁺ are created by the second dissociation or by the dissociation of the water solvent.

Therefore, in the second equation, we can cancel [H⁺] and [HS⁻], simplifying the second equation to 1.0 × 10^(-14) = [S²⁻]

We have our answer! [S²⁻] = 1.0 × 10^(-14)

Explanation:

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Answer 2

Answer:

Ka1 = 1.1 × 10^(-7) = [H⁺][HS⁻]/[H₂S] and Ka2 = 1.0 × 10^(-14) = [H⁺][S²⁻]/[HS⁻]

The two quantities [H⁺] and [HS⁻] are virtually equal, as a negligible number of H⁺ are created by the second dissociation or by the dissociation of the water solvent.

Therefore, in the second equation, we can cancel [H⁺] and [HS⁻], simplifying the second equation to 1.0 × 10^(-14) = [S²⁻]

We have our answer! [S²⁻] = 1.0 × 10^(-14)

Explanation:

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