Question

what is S.H.M.calculate the energy of the particle in S.H.M
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Answer 1

Explanation:

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At the mean position, the velocity of the particle in S.H.M. is maximum and displacement is minimum, that is, x=0.

Therefore, P.E. =1/2 K x2 = 0 and K.E. = 1/2 k ( a2 – x2) = 1/2 k ( a2 – o2) = 1/2 ka2. Thus, the total energy in simple harmonic motion is purely kinetic.

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Answer 2

Answer:

ANSWER

K.E = P.E

2

1

kx

2

=

2

1

mv

2

v=ω

A

2

−x

2

2

1

kx

2

=

2

1

m(ω

A

2

−x

2

)

⇒x=

2

A

x=Asin(ωt)

x=

2

A

2

A

=Asinωt

ωt=(

4

π

)

r=(

4ω

π

)=

42π

π×T

=

8

8

=1sec