Question

what is sec^2 x/tan x​

Answer 1

Answer:

write question in proper way

Answer 2

EXPLANATION :

We know,

${ \boxed { \sf{ \cos 2x} = 2 { \cos}^{2} x - 1}}$

$\sf{ \cos 2x} = 2 { \cos}^{2} x - 1$

$\implies \sf \frac{1 - { \tan}^{2}x }{1 + { \tan}^{2}x } = 2 { \cos}^{2} x - 1$

$\sf \implies \: 2 { \cos}^{2} x = \frac{1}{1 + { \tan}^{2} x}$

$\sf \implies { \sec}^{2} x = \frac{1 + { \tan}^{2} }{2}$

Multiplying 1/ tan x both side

$\sf \implies { \boxed{ \sf\frac{ { \sec}^{2}x }{ \tan \: x} = \frac{1}{2} ( \cot \: x + \tan \: x)}}$