what is sin**-1 (0.5)
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sin
−
1
(
−
0.5
)
=
sin
−
1
(
−
1
2
)
Is there a special angle with
sin
t
=
1
2
?
Yes,
t
=
π
6
.
But we want
sin
t
=
−
1
2
, so we want an answer in quadrant 3 or 4.
sin
−
1
(
x
)
always gives us a
t
between
−
π
2
and
π
2
, so we want
t
=
−
π
6
sin
−
1
(
−
0.5
)
=
π
6
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