What is
sin 3x + cos 3x + 4 sin x-3 sin x +
3 cos x - 4 cos x
Answers
Answered by
0
Answer:
please make me brainlist please please please
Step-by-step explanation:
cos^3 x.sin3x + sin^3 x.cos 3x = 3/4
==> cos^3 x(3sin x - 4 sin^3 x)
+sin^3 x(4cos^3 x - 3 cos x) = 3/4
=> 3sin x.cos^3 x - 4cos^3 x.sin^3 x
+4sin^3 x.cos^3 x -3cos x.sin^3 x= 3/4
=> 3sin x.cos x(cos^2 x - sin^2 x) = 3/4
=> 4sinx.cosx.cos 2x = 1
=> 2.sin 2x.cos 2x = 1
=> sin 4x = sin (π/2)
=> 4x = nπ + (-1)^n .π/2
=> x = nπ/4 + (-1)^n.π/8
Similar questions