Question

what is sin(cos^{-1} (sqrt2}}{2)?

Answer 1

Answer:

radians therefore cos(π4)=√22

cos−1(cos(π4))=cos−1(√22)→π4=cos−1(√22)

Sub this into original equation

sin(cos−1(√22))→sin(π4)

sin(π4)=√22

Answer 2

√2

Step-by-step explanation:

sin(cos^-1√2)(2)

=sin{sin^-1(1/√2)}(2)

=1/√2(2)

=√2