Question

What is sin2A=2sinAcosA when A=45°

Answer 1

When A = 45° then, sin2A = sin2×45° = sin90° = 1

As we know that : sin90° = 1

Answer 2

$\huge \boxed {\texttt {\fcolorbox {red} {aqua} {SOLUTION ;}}}$

Given, A = 45°

Sin2A = sin90° = 1

2sinA cos A = 2 × sin45° ×cos 45° = 2×1 ×1 = 2