Question

what is sin2theta×cos2theta​

Answer 1

Answer:

sin 2 =θ − ( 1 − sin 2 θ ) = 0

sin 2 θ − 1 + sin 2 θ = 0

2 sin 2 θ = 1

sin 2 θ = 1 /2

sin θ =  + 1 /√ 2