Question

what is solubility of Pbl2 if the solubility product is 7.1×10^-9
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Answer 1

Answer:

The expression for the solubility product is :

K

sp

=[Pb

2+

][I

−

]

2

7.1×10

−9

=[Pb

2+

][0.05]

2

[Pb

2+

]=2.84×10

−6

M.

Convert the unit from mole per liter to mg/mL.

Molarity×Molar mass=2.84×10

−6

L

mol

×207

mol

g

=5.9×10

−4

g/L=5.9×10

−4

mg/mL=X×10

−4

mg/mL

Hence, X=6

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Answer 2

Answer:

can you explain the question more clearly