Question

what is solution of maths of ncrt chapter of 9 exercise 9.3 Question. 1 to last​

Answer 1

QUESTION NUMBER 1 ANSWER IS THIS

Access Answers to NCERT Class 9 Maths Chapter 9 – Area of Parallelograms and Triangles Exercise 9.3

1. In Fig.9.23, E is any point on median AD of a ΔABC. Show that ar (ABE) = ar(ACE).

Ncert solutions class 9 chapter 9-9

Solution:

Given,

AD is median of ΔABC. ∴, it will divide ΔABC into two triangles of equal area.

∴ar(ABD) = ar(ACD) — (i)

also,

ED is the

median of ΔABC.

∴ar(EBD) = ar(ECD) — (ii)

Subtracting (ii) from (i),

ar(ABD) – ar(EBD) = ar(ACD) – ar(ECD)

⇒ar(ABE) = ar(ACE)

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