what is square root of 42.25
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Always remember that any number ending with 25 can be a perfect square if it's other digits can be expressed in the form of n(n+1), that is, the product of a natural number multiplied by the next natural number. Moreover, it's square root is 10n+5. It has also been proved in 8th standard NCERT book. I am proving it here too.
So, using this, 42.25=4225/100. Now, in 4225, if we remove 25, the remaining digits are 42=6*7 =6(6+1). Hence, square root of 4225 is 10(6)+5 =65. So, square root of 4225/100=65/10=6.5.
So, using this, 42.25=4225/100. Now, in 4225, if we remove 25, the remaining digits are 42=6*7 =6(6+1). Hence, square root of 4225 is 10(6)+5 =65. So, square root of 4225/100=65/10=6.5.
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Hey there!
Square root of 42.25
= √4225/100
Factors of 4225
5 | 4225
5 | 845
13 | 169
13 | 13
| 1
= √4225/100
= √5 x 5 x 13 x 13/10 x 10
= 5 x 13 / 10
= 65/10
= 6.5 Ans.
Hope it helps You!
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