Question

what is sue sum of all
the terms
of the A.P, 201, 208, 215,---, 369​

Answer 1

Answer:

i think answer is 299

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Answer 2

Step-by-step explanation:

Given:A.P, 201, 208, 215,---, 369

1. a=201
2. d=208-291=7.
3. an=369.

To find: n=? Sn=?.

Formula:

• nth term:

$an = a + (n - 1) \times d$

• Sum of nth term:

$sn \\ \frac{n}{2} \times (2 \times a + (n - 1) \times d))$

(I). 369=201+(n-1)×7

=> 369-201=(n-1)×7

=> 168/7=n-1

=> 24+1=n.

=> n=25.

(ii). Now,

S25=25/2(2×201+(25-1)×7)

=> 25/2(402+24×7)

=> 25/2×570

=> 25×285

S25= 7125.