Question

What is sum of 24 term of series root 2 + root 8 + root 18 +root 32 + ......

Answer 1

Answer: 300root2

Step-by-step explanation:

root2+root8+root18+root32+....

=root2+2root2+3root2+....,

=root2(1+2+3+.....+24)

=root2x24x25/2 (because sum of first n natural numbers is n(n+1)/2 )

=300root2 or root(180000)