Question

What is sum of interior angles of a polygon having 6 sides

Answer 1

Step-by-step explanation:

1.Sum of interior angles of a polygon of 6 sides =

(Side -2)×180°

(6-2)×180°

4×180°

720°.. Ans

2.Now sum of interior angles of polygon of 8 sides =(8-2)×180°

6×180°=1080°..Ans

3. Sum of interior angle of polygon of 10 sides = (10-2)×180°= 1440°...Ans

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Answer 2

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The sum of the measures of the interior angles of a polygon with n sides is (n – 2)180. If you count one exterior angle at each vertex, the sum of the measures of the exterior angles of a polygon is always 360°.