what is sum of measurs of exterior angles of polygons . draw pictures
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Answer:
in triangle = 360°
in pentagon= 540°
raja8556:
so now I am in 11th class
Answered by
1
hey mate here is your answer
✓let the no of side of the polygon be "n"
✓so angle on each corner is
(n-2)*180°)/n
✓so sum of exterior angle is
180(n)- (n-2)180°
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