Question

what is sum of n terms of ap and gp​

Answer 1

Explanation:

$\huge\blue{HELLO\:MATE}$

IN AN AP

LET a BE THE 1ST TERM

d BE THE COMMON DIFFERENCE

AND

n BE THE NO. OF TERMS

THEN SUM OF N TERMS (Sn)=n/2[2a+(n-1)d]

IN A GP

LET a BE THE 1ST TERM

r BE THE CONSTANT RATIO

AND

n BE THE NO. OF TERMS

THEN SUM OF N TERMS (Sn)=

$a \dfrac{( {r}^{n} - 1) }{(r - 1)}$