what is t.s.a of a cone whose radius is r/2 and slant height is 2l?
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TSA of a cone = pi*r(l+r)
=2*22/7*r/2( 2l+r/2)=. 22/7*r(r+4l)/2 =22/7*r(r+4l)/2
=2*22/7*r/2( 2l+r/2)=. 22/7*r(r+4l)/2 =22/7*r(r+4l)/2
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The TSA of cone= pie(r)(r+l)
Then the TSA of newly
formed cone= pie(r^2+lr)
Pie[(r/2)^2]+(2lĂr/2)
Pie[(r/4)]+(2lr/2)
Pie(r+4lr/4)
Pie[(1/4r^2)+lr]
Do the TSA becomes 1/4
TSA=1/4Pie(r)(r+l)
Then the TSA of newly
formed cone= pie(r^2+lr)
Pie[(r/2)^2]+(2lĂr/2)
Pie[(r/4)]+(2lr/2)
Pie(r+4lr/4)
Pie[(1/4r^2)+lr]
Do the TSA becomes 1/4
TSA=1/4Pie(r)(r+l)
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