Question

What is t10 for the A.P √2, √8 , √18......

Answer 1

Step-by-step explanation:

Please refer to the attachment

Answer 2

Answer:

The 10^{th} term of the given AP series is 10 $\sqrt2$.

Step-by-step explanation:

Given:

What is t10 for the A.P √2, √8 , √18......

Solution:

a = $\sqrt2$,  

$\sqrt8 = \sqrt{(2 \times 2) \times 2} = 2 \sqrt2$

$\sqrt{18} = \sqrt{(3 \times 3) \times 2} = 3 \sqrt2$

a = $\sqrt2$,

d = $2 \sqrt2 -  \sqrt2 = \sqrt2$

t10 = a + 9d

= $\sqrt2 + 9 \sqrt2$

= 10 $\sqrt2$

Result:

The 10^{th} term of the given AP series is 10 $\sqrt2$.

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