Question

What is t11 for an A.P., if a=180 and d
=7 ?​

Answer 1

$t_{11}= 250$

Given :

a = 180 , d = 7

To Find :

$t_{11} = ?$

Formula Applied :

$t_n = a+(n-1)d$

Solution :

$\implies t_n = a+(n-1)d$

$\implies t_{11} = 180 + (11-1)7$

$\implies t_{11}=180 + (10)7$

$\implies t_{11} = 180 + 70$

$\implies t_{11} = 250$

Answer 2

$t_{11}= 250$

Given :

a = 180 , d = 7

To Find :

$t_{11} = ?$

Formula Applied :

$t_n = a+(n-1)d$

Solution :

$\implies t_n = a+(n-1)d$

$\implies t_{11} = 180 + (11-1)7$

$\implies t_{11}=180 + (10)7$

$\implies t_{11} = 180 + 70$

$\implies t_{11} = 250$