what is tension in string in given figure,if coefficient of friction is 0.2. M1:20kg and m2:40kg
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Answer:
Tension = 130 N
Explanation:
Force along incline on 40 Kg Mass= Wight componen-Tension-Friction
= 40 Sin30 . g -Tension- 40.Mu.Cos 30 g
= 200-T-70
40 . a = 200 - T-70
40a = 130 - T ....(1)
Force along incline on 20 Kg Mass
=Tension -20 Sin30 . g - 20Mu.Cos30 g upwards
= T-100-35
20 . a = T-135- ....(2)
T = 20 a+135 ....(3)
40 a = 130 -2a-135
20 a= -5
a=-1/4
T=-5+135
T= 130 N
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