Question

What is $(-8)^{-4/3}$ in radical notation?
Do you put the negative on the inside or outside of the cube root?

Answer 1

Answer:-

If you want to write this in radical expression,then follow these steps,

$\sf { - 8}^{ \frac{ - 4}{3} }$

$\sf = {( - 8)}^{ - 4 \times \frac{1}{3} }$

Now,

$\sf \sqrt[3]{x} = {x}^{ \frac{1}{3} }$

So,

$\sf {( - 8)}^{ - 4 \times \frac{1}{3} }$

$\sf = \sqrt[3]{ { (- 8)}^{ - 4} }$

This is the radical expression.

If the power is negative, write it inside the root.

Answer 2

Answer:

If you want to write this in radical expression,then follow these steps,

\sf { - 8}^{ \frac{ - 4}{3} }−8

3

−4

\sf = {( - 8)}^{ - 4 \times \frac{1}{3} }=(−8)

−4×

3

1

Now,

\sf \sqrt[3]{x} = {x}^{ \frac{1}{3} }

3

x

=x

3

1

So,

\sf {( - 8)}^{ - 4 \times \frac{1}{3} }(−8)

−4×

3

1

\sf = \sqrt[3]{ { (- 8)}^{ - 4} }=

3

(−8)

−4

This is the radical expression.

If the power is negative, write it inside the root.

hope it helps