Question

What is
$\sqrt{ \frac{25}{36} - { \beta }^{2} }$

Answer 1

$\sqrt{ \frac{25}{36} - { \beta }^{2} } \\ = \sqrt{ \frac{ {5}^{2} }{ {6}^{2} } - { \beta }^{2} } \\ = \sqrt{( \frac{5}{6} + \beta )( \frac{5}{6} - \beta ) }$
I HOPE IT HELPS YOU...!!!