what is tha answer of this y2+y/2-3=0
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y²+y/2-3=0
2y²+y-6=0
2y²+4y-3y-6=0
2y(y+4) -3(y+4) =0
(y+4) (2y-3) =0
(y+4) =0 or (2y-3) =0
y=-4 or y=3/2
2y²+y-6=0
2y²+4y-3y-6=0
2y(y+4) -3(y+4) =0
(y+4) (2y-3) =0
(y+4) =0 or (2y-3) =0
y=-4 or y=3/2
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