Question

What is tha oxidation state of xenon in xeo4?

Answer 1

$oxn \: state \: of \: o \: is \: - 2 \: and \: the \: total \: charge \: is \: zero \\ oxn \: state \: of \: xe \: is = x - 2 \times 4 = x - 8 = 0 \\ therefore \: xe \: is \:in \: + 8 \: oxn \: state$