Question

What is the 100th term of the sequence with a1 = 222 and d = -5?

Answer 1

Answer:

717

Step-by-step explanation:

222+99x(-5)

222+495

=717..

Hope it helps..

Please mark it brainliest..

Follow me!

Answer 2

Answer:

-273

Step-by-step explanation:

an = a1+(n1-d )

a100= 222+(99 ×-5)

a100= 222- 495

a100 = - 273