Question

What is the 10th term of an arithmetic sequence whose 1st term is 14 and the common difference is -5?​

Answer 1

Answer:

answer is -31

Step-by-step explanation:

the first term is 14

which is the value of a

first term =a =14

d=-5

therefore

t10 = a+(n-1) d

= 14 +(10-1 ) -5

= 14- 45

= -31

hence the 10th term is -31