Question

what is the 10th term of the sequence defined by an=(n-1)(2-n)(3+n)?

Answer 1

put 10 in the given equation
an=9×(-8)×13= - 936 is the 10th term of the sequence.

Answer 2

Answer:

-936

Step-by-step explanation:

Given,

Sequence: $a_{n}$ = (n-1)(2-n)(3+n)

To Find,

The 10th term.

$a_{10}$ = (n-1)(2-n)(3+n)

     = (10-1)(2-10)(3+10)

     = (9)(-8)(13)

     = -936

Hence, the answer is -936.

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