Question

what is the 11th term for the given arithmetic progression
2,6,10,14,18​

Answer 1

Answer:

a= 2

D = 6-2= 4

n= 11 (given)

Now , Putting Formula

tn =a+n-1(d)

=2+11-1(4)

=2+10(4)

=2+40

= 42

So the 11 th term will be 42

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