What is the 12th term of the linear sequence below? 13 , 7 , 1 , − 5 , − 11 , . . .
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13,7,1,-5,-11 it's an A.P. Series
d=7-13=1-7=-5-1=-11+5=-6
First term a=13
We have to find out 12 th term
T12=a+(n-1)d
=13+(12-1)*-6
=13+11*-6
=13-66
=-53
The 12th term is - 53
Or if we observe there is difference of - 6 in every two consecutive term so we can get the next term by adding - 6. And repeat the process until we get the 12th number.
6th no. -11+-6=-17
7thh -17+-6=-23
8th -23+-6=-29
9th -29+-6=-35
10th -35+-6=-41
11th -41+-6=-47
12th -47+-6=-53
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