Question

What is the 14 th term of an A.P. whose first term is 17 and the sum of its first 27 terms is 1161?

Answer 1

s=n/2(2a+(n-1)d)

1161=27/2(2*17+(27-1)d)

86  =(34+26*d)

86-34=26*d

52  =26*d

2    =d

tn = a+(n-1)d
t14= 17+(14-1)2
     = 17+13*2
     =17+26
     =43 answer