Question

. What is the 16th term of an AP. Whose first two are 100, 105?​

Answer 1

AnswEr :

16th term of an AP is 175.

So, here we're given with AP and common difference & we're supposed to find out the required term of an AP.

GiveN:

• A.P = 100, 105

• Common difference, d = 105 - 100 = 5

Now, we'll use the respective formula used to calculate the term of an AP.

Let us assume that the 16th term of an AP is the nth term itself.

we know that,

$\longrightarrow$ An = a+ (n-1)d

$\longrightarrow$ A16 = 100 + (16-1) × 5

$\longrightarrow$ A16 = 100 + 15 × 5

$\longrightarrow$ A16 = 100 + 75

$\longrightarrow$ A16 = 175

$\therefore$ 16th term of an AP is 175.

⠀⠀⠀Additional information :

• nth Term of an AP => an = a + (n − 1) × d

• Sum of N Terms of AP => S = n/2[2a + (n − 1) × d]

• Sum of AP when the last term is given => S = n/2 (first term + last term)

Answer 2

Answer :

The 16th term of an A.P. is 175