Question

What is the 18 th term of ap n(n-3)÷n+4

Answer 1

Answer:

a18 = 135/11

Explanation:

an = [n(n-3)]/(n+4)

If n = 18 then

a18 = [18(18-3)]/(18+4)

= (18×15)/22

= (9×15)/11

= 135/11

Therefore,

18th term in the series = 135/11

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