Question

What is the 30th term of the linear sequence below?
−
4
,
−
1
,
2
,
5
,
8
,
.
.
.

Answer 1

Explanation:

As a term of the sequence has constant difference with preceeding term, (19−13=13−7=7−1=6), this is an arithmetic sequence with first term as 1 and constant difference as d.

As the nth of such a series is given by a+(n−1)d) where n is 30 i.e.

1+29⋅6)

or

175

sorry I had given you a wrong answer by mistake and I can't delete my answer so you report it... again I am very sorry

Answer 2

Answer:

The 30th term of the given linear sequence is 83

Step-by-step explanation:

The given sequence is $-4,-1,2,5,...........$

We are required to find the 30th term of the given sequence.To find it we must analyze the pattern of the given series.

The given series is an arithmetic progression with an common difference of 3 and first term -4.Therefore,for the progression $a=-4,d=3$

The nth term of the arithmetic progression is given by the relation

$a_{n}=a+(n-1)d$

Therefore,the 30th term of the series must become $a_{30}=a+(30-1)d=a+29d$

Substituting the known values in the above relation,we get

$a_{30}=-4+29(3)=83$

Therefore,the 30th term of the given linear sequence is 83

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