Question

What is the 30th term of the linear sequence of -4 -1 2 5 8

Answer 1

Answer:

30th term = 83

Step-by-step explanation:

Given sequence,

-4 , -1 , 2 , 5 , 8

the given sequence is of AP

first term, a = -4

common difference, d = 8-5 = 5-2 = 2-(-1) = -1-(-4) = 3

we have to find 30th term, $a_{30}= \ ?$

n = 30

nth term is given by,

$a_n=a+(n-1)d$

30th term,

$a_{30}=-4+(30-1)(3)\\a_{30}=-4+29(3)\\a_{30}=-4+87\\a_{30}=83$