Question

What is the 32nd term of the arithmetic sequence where a1 = −33 and a9 = −121?

Answer 1

a1=-33
hence , first term = a = -33
a9=a+8d=-121

-33+8d=-121
8d= -88
hence , d= -11

a32= a+31d = -33+ 31×-8
= -33 -248
= -281